find the area of BEF in a square ABCD and area of BEC is equal to 3, area of EFD is equal to 5 and area of BFA is equal to 4
Answers
THE QUESTION ASKED IS WRONG FOR EXPLANATION SEE ATTACHED IMAGE
Answer:
The Area Δ BFE is 11.04 unit²
Step-by-step explanation:
Given as :
From the figure
Let The each side of square ABCD = x unit
i.e BA = AD = DC = CB = x unit
Area Δ BAF = 4 unit²
Area Δ EDF = 5 unit²
Area Δ BCE = 3 unit²
Let FD = ED = CE= y unit
So, AF = ED = x - y unit
In Δ BAF
Area Δ BAF = × BA × AF
Or, 4 × 2 = x × (x - y )
Or, x² - x y - 8 = 0 ...........A
Again
Area Δ EDF = × FD × ED
Or, 5 = × FD × ED
or, × y × y = 5
Or, y² = 10
∴ y = √10 .............B
Now, from eq A and eq B
x² - x × √10 - 8 = 0
Solving the quadratic equation
x = 4.8 , - 1.6
Or, x = 4.8
So, The measure of side AD = AF + FD
i.e AD = x - √10 + √10
Or, AD = 4.8 + 0
So, AD = 4.8 unit
i,e each side of square = 4.8 unit
Now,
Area of square ABCD = side × side
Or, Area of square ABCD = 4.8 unit × 4.8 unit
∴ Area of square ABCD = 23.04 unit²
So, Area Δ BFE = Area of square ABCD - ( Area Δ BAF + Area Δ FDE + Area Δ BCE )
or, Area Δ BFE = 23.04 unit² - (4 unit² + 5 unit² + 3 unit² )
Or, Area Δ BFE = 23.04 unit² - 12 unit²
∴ Area Δ BFE = 11.04 unit²
Hence, The Area Δ BFE is 11.04 unit² Answer