Question

Find the area of canvas required to make a conical tent 14m high and 96m in diameter . Given that 20% of the
canvas is used in folds and stitcings.

Answer 1

Answer:

9428 4/7 m² or 9428.57 m²

Step-by-step explanation:

Given,

height, h = 14 m

diameter = 96 m

⇒radius, r = 96/2 = 48 m

Since CSA is needed to find the area of the canvas required,

l = √r²+h² = √48²+14² = 50 m

⇒CSA = πrl = 22/7 * 48 * 50

Solving we get 52,800/7 m² or 7542.86 m²

Let the area of the canvas required be x m²

Given 20% of the canvas is used in folds and stichings,

∴ x - 20% of x = 52,800/7 m²

x - 20/100 * x = 52,800/7 (on cancelling 20/100 we get 1/5)

On taking LCM,

(5x - x)/5 = 52,800/7 (taking 5 to RHS)

4x = (52,800 * 5)/7 (taking 4 to RHS)

x = (52,800 * 5)/7 * 4

On solving we get 9428 4/7 m² or 9428.57 m²

Hope it helps...♥☺