Question

Find the area of cardboard required to prepare a closed box of dimensions 12 cm x 10 cm * 8 cm.​

Answer 1

Answer:

T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.

Given l=12 cm,b=10 cm,h=8 cm

T.S.A=2((12)(10)+(10)(8)+(8)(12))

=2(120+80+96)

2(296)=592 cm

Answer 2

Answer:

592 cm²

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