find the area of circle circumscrimbing a sauare of side 6 cm
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area of square = 4a square =4×4 =16 . ans. hope that this will help you out.!!
durva3:
is this right ans??
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3
diary, eternal must be the diagonal of the square..
So diameter is


therefore radius is 1/2 of diameter

area of circle




So diameter is
therefore radius is 1/2 of diameter
area of circle
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