Question

find the area of circle where 4 squares of area 16 are inscribed in it
○□​

Answer 1

Given :

Area of each square = 16 sq unit

To Find ;

Area of circle in which the 4 squares of area 16 sq  units are inscribed = ?

Solution :

Since the area of each square is 16 sq units and we know  that area of a square is square of its side length i.e.:

$A = s^2$

Where S is side length .

So, the side length of each of the given squares will be :

$s^2= 16$

⇒$s = \sqrt{16}$

Or, s = 4 units

Now  in this case each side of square will act  as the radius of 4 semicircles that we have .

So, area of 4 semicircles = $4 \times (\frac{\pi \times 4^2}{2})$    ( ∴area of a semicircle $= \frac{\pi \timrs r^2}{2}$)

                                         $= 4 \times (\frac{16 \pi }{2})$

                                          =$32 \pi$

Hence , total area of circle = $(16 \times 4) + 32 \pi$

                                            = 164.48 sq units  

So, the area of circle is 164.48 sq units .

Answer 2

Answer:

Step-by-step explanation:

Observe the image..you can consider origin anywhere you'll get the same radius..