Find the area of circle x^२ + y^२ =४ using integration
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0
Answer:
Equation of the circle is x
2
+y
2
=4
∴y=
4−x
2
But the area element is given by
∴ydx=
4−x
2
dx
Integrating both the sides with x ranging from -2 to 2
∴A=∫
−2
2
ydx=∫
−2
2
4−x
2
dx
Let x=2sinθ ⇒dx=2cosθdθ
∴A=∫
−π
π
4−4sin
2
θ
2cosθdθ=∫
−π
π
4cos
2
θdθ
=2∫
−π
π
(1+cos2θ)dθ
=4π
Answered by
8
Given equation of circle is
can be rewritten as
It means, circle having centre (0, 0) and radius, r = 2 units.
Now, see the attachment.
We concluded that circle divided in to 4 equal parts in 4 quadrants, So we find the area in first quadrant with respect to x - axis from x = 0 to x = 2 and multiply by 4 to find the required area.
So, required area of circle is
Formulae Used :-
Additional Information :-
Attachments:
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