Question

Find the area of curved surface and total surface are of right circular cylinder whose height and radius of the base are 20 cm and 14 cm respectively.​

Answer 1

Answer:

CSA = 1760 cm²

TSA = 2992 cm²

Given :-

• Height = 20 cm
• Radius = 14 cm

To find :-

• Curved surface area (CSA) = ?
• Total surface area (TSA) = ?

Solution :-

$\sf{CSA \: of \: cylinder = 2\pi \: r \: h }$

$\implies \sf{CSA = 2 \times \dfrac{22}{7} \times 14 \times 20}$

$\dashrightarrow \: \sf{CSA = \dfrac{2 \times 22 \times \cancel {14} \times 20}{ \cancel7} }$

$\dashrightarrow \sf{CSA = 2 \times 22 \times 20 \times 2}$

$\: \: \therefore \: \boxed{ \bf{CSA = 1760 \: cm {}^{2} }}$

Now for finding TSA,

$\\ \sf{TSA = 2\pi \: r(r + h)}$

$\leadsto \sf{TSA = 2 \times \dfrac{22}{7} \times 14 \times (14 + 20) }$

$\sf{ \longrightarrow \: TSA = 2 \times 22 \times 2(34)}$

$\dashrightarrow \: \sf{TSA = 2 \times 22 \times 68}$

$\therefore \boxed{ \bf{TSA = 2992 \: cm {}^{2} }}$

Answer 2

QuestioN :

Find the area of curved surface and total surface are of right circular cylinder whose height and radius of the base are 20 cm and 14 cm respectively.​

GiveN :

Height = 20 cm

Radius = 14 cm

To FiNd :

The area of curved surface.

ANswer :

$\sf The\: area \:of \:curved \:surface \:is \: 2992^2.$

SolutioN :

$\sf CSA=2$Π$\sf rh$

$\sf \rightarrow 2\:x\:\frac{22}{7} \:x\: 14\:x\:20$

$\sf \rightarrow 2\:x\:22\:x\:20\:x\:2$

$\sf \rightarrow 1760cm^2$

$\sf TSA=2$Π$\sf r(r+h)$

$\sf \rightarrow 2\:x\:\frac{22}{7} \:x\: 14( 14+20)$

$\sf \rightarrow 2\:x\:22\:x\:2\:x\:34$

$\sf \rightarrow 2992cm^2$

∴Hence, The area of curved surface is 2992cm².

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