Question

find the area of each of the following fields. all dimensions are in meters ​

Answer 1

Answer:

area of 1st part =

$\frac{1}{2} \times 40 \times 70 \\ 20 \times 70 \\ 1400 \\ area \: of \: 2part \: = \frac{1}{2} \times 80(20 + 40) \\ 40 \times 60 \\ 2400 \\area \: of 3 \: part \: = \frac{1}{2} \times 20 \times 40 \\ 10 \times 40 \\ 400 \\ area \: of \: 4part \: = \frac{1}{2} \times 80 \times 40 \\ 40 \times 40 \\ 2400 \\ area \: of5 \: part \: = \frac{1}{2} \times 60 \times 40 \\ 30 \times 40 \\ 1200 \\ area \: of \: 6part = \frac{1}{2} \times 30 \times 50 \\ 15 \times 50 \\ 750$

area of all dimensions =1400 +2400+400+2400+1200+750=8550

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