find the area of each of the following figure.
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Taking Rect. ABCH
L=4cm and B= 1cm
so, A of ABCH= Lx B
=4 x 1 = 4cm^2
Taking Rect. HDEL
L=2 and B= 1
so, A= Lx B = 2×1 = 2 cm^2
Taking Rect. LFGK
L=4 and B =1
so, A = Lxb = 4x1 = 4 cm^2
Taking Rect. KHIT
L= 2 and B= 1
A of KHIT= l x b = 2 x 1 = 2 cm^2
A of the given fig. = A. of ABCH + A of HDEL + A of LFGK + A og KHIT
= (4+2+4+2)cm^2
= (8 + 4)cm^2
= 12 cm^2
Step-by-step explanation:
Here, I divided the given fig. into 4 parts to get the answer....
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