Question

find the area of each of the following shapes of pol

Answer 1

Answer:1018 cm sq.

Step-by-step explanation:

Answer 2

area of the shapes
1 st part
let the right angle at c
ab is hypoteneous ac = 60 bc=11
area of triangle
$1 \div 2 \times 11\times 60 \\ 11 \times 30 \\ 330$

${ab}^{2} = {11}^{2} + {60}^{2} \\ {ab }^{2} = 121 + 3600 \\ ab = \sqrt{3721} \\ ab =61$
area of trapizeum
1/2(sum of parallel sides) h
1/2 (26+61)18
1/2*87*18
87*9
783
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