Question

find the area of each of the following triangles
AB is 8cm,BC is 10cm,CA is 6cm​

Answer 1

☯︎ Given :-

• Sides of triangle = 8cm, 10cm, 6cm

☯︎ To Find :-

• Area of Triangle

☯︎ Solution :-

AB = 8cm

BC = 10cm

AC = 6cm

Semi perimeter :-

=> $\tt\dfrac{A+B+C}{2}$

=> $\tt\dfrac{8+10+6}{2}$

=> $\tt\dfrac{24}{2}$

=> $\large{\red{\underline{\blue{\boxed{\pink{12\:cm}}}}}}$

Area :-

$= > \sqrt{s(s - a)(s - b)(s - c)}$

$= > \sqrt{12(12 - 8)(12 - 10)(12 - 6)}$

$= > \sqrt{12(4)(2)(6)}$

$= > \sqrt{2 \times 2 \times 3 \times 2 \times 2 \times 2 \times 2 \times 3}$

$= > 2 \times 2 \times 2 \times 3$

$= > \large{\red{\underline{\purple{\boxed{\orange{24 \: cm}^{2}}}}}}$

Hope it helps......