find the area of each of the following triangles....AB is 8cm,BC is 10cm,CA is 6cm
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AB = 8cm
BC = 10cm
CA = 6cm
Perimeter = 8 + 10 + 6 = 24cm
s = Perimeter/2 = 24/2 = 12cm
Hence,
Area of triangle (only using sides)
= √s(s-a)(s-b)(s-c)
= √12(12-8)(12-10)(12-6)
= √12*4*2*6
= √576
= 24cm²
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Answer:
find the area of each of the following triangle 6cm aur dusra 10cm
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