Question

find the area of each triangle​

Answer 1

a) 120 cm²

b) 60 cm²

Step-by-step explanation:

Pythagoras theorem = H²(hypotense)=P²(perpendicular)+B²(base)

a) H²= P²+B²

= (26)²= P²+(10)²

= 676 = P²+100

= 676 - 100 = P²

= 576 = P²

= √576 = P

= √24×24 = P

= 24 = P

Hence, P = 24

Area of the triangle = 1/2×b×h

= 1/2×10×24

= 120 cm²

b) Let's suppose a line between the triangle as we have to use the Pythagoras theorem. So, there's becomes two triangles after making a line in between. Now, name the both triangles as triangles (i) and triangle (ii).

Click on the upper image to see the answer.

If any problem, then u can ask me down in the comments.

Answer 2

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$\blacksquare \: \purple{ \pmb {\sf{Formulae \: Applied : }}}$

$\bigstar \: \pmb{ \bf \underline{\underline \pink{{hypotenuse}^{2} = \: {perpendicular}^{2} + {base}^{2}}}}$

________________________________

$\underbrace { \dagger\pmb{ \bf \: answer - 1st}}$

$\rm : \implies \: {26}^{2} = {perpendicular}^{2} + {10}^{2} \\ \rm \: : \implies 676 = {perpendicular}^{2} + 100$

$\rm : \implies \: {perpendicular}^{2} = 676 - 100 \\ = 576$

$\rm \: : \implies \: perpendicular = \sqrt{576} \\ \fbox{= 24}$

$\bigstar \: \sf \frac{1}{2} \times base \times height = area$

$\rm : \implies \frac{1}{2} \times 10 \times 24 \\ \rm : \implies \cancel\frac{1}{2} \times 10 \times \cancel{ 24} \: ^ {12}$

$\rm : \implies 12 \times 10 = 120$

$\blacksquare \underline{ \underline{ \pmb {\bf\: area = {120}cm^{2}} }}$