Math, asked by anshu239, 1 year ago

find the area of enclosed by the figure

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Answered by Anonymous
7
hii!!

here's ur answer...

let we divide them into two parts.

one is rectangle and other is trapezium.

given length of the rectangle is 20m and breadth of the rectangle is 10m.

area of the rectangle = l×b

= 20×10

= 200m²

now,

base of the trapezium is 10m and the parallel side is 5m.

height is = 26-20

= 6m

area of the trapezium = 1/2×h(b1+b2)

= 1/2×6(5+10)

= 3×15

= 45m²

hence area of the whole figure = 200+45

= 245m²

hope this helps u..!

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