find the area of enclosed by the figure
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hii!!
here's ur answer...
let we divide them into two parts.
one is rectangle and other is trapezium.
given length of the rectangle is 20m and breadth of the rectangle is 10m.
area of the rectangle = l×b
= 20×10
= 200m²
now,
base of the trapezium is 10m and the parallel side is 5m.
height is = 26-20
= 6m
area of the trapezium = 1/2×h(b1+b2)
= 1/2×6(5+10)
= 3×15
= 45m²
hence area of the whole figure = 200+45
= 245m²
hope this helps u..!
here's ur answer...
let we divide them into two parts.
one is rectangle and other is trapezium.
given length of the rectangle is 20m and breadth of the rectangle is 10m.
area of the rectangle = l×b
= 20×10
= 200m²
now,
base of the trapezium is 10m and the parallel side is 5m.
height is = 26-20
= 6m
area of the trapezium = 1/2×h(b1+b2)
= 1/2×6(5+10)
= 3×15
= 45m²
hence area of the whole figure = 200+45
= 245m²
hope this helps u..!
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