Find the area of enclosed figure
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Answer:
rectangle 2×l+b
2×14+8=44sq
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Area of figure=area of rectangle+area of two trapeziums
Area of rectangle = 8*14=112 cm sq
Area of trapezium= 1/2 sum of parallel sides * height
Height=5.5cm.
Area of trapezium= 1/2*(16+8)*5.5 =66cm sq
Area of two trapeziums=2*66=132cm sq
Area of enclosed figure=132+112=244cm sq
Therefore, answer=244 cm sq
Area of rectangle = 8*14=112 cm sq
Area of trapezium= 1/2 sum of parallel sides * height
Height=5.5cm.
Area of trapezium= 1/2*(16+8)*5.5 =66cm sq
Area of two trapeziums=2*66=132cm sq
Area of enclosed figure=132+112=244cm sq
Therefore, answer=244 cm sq
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