find the area of enclosed figure
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Answer:
we will find the area by dividing the figure into 2 parts
Area of square= side × side
=20×20
=400 cm^2.
Area of trapezium=1/2×(sum of parallel sides)×distance between parallel sides
=1/2×(6+20)×8
=1/2×26×8
=1/2×208
=104 cm^2.
Area of whole figure=area of square+area of trapezium
=400+104
=504 cm^2
Step-by-step explanation:
504 cm^2 is the correct answer. hope it helps. have a nice day.
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Answered by
0
(i) Area = area of □AEDC+ area of △ABC [ref. image (i)]
=4×4+
2
1
×4×2
=16+4=20cm
2
(ii) Area = are of trapezium DEFC+ area of □ABCF [ref. image (ii)]
=
2
8
×(7+18)+18×18
=4×25+18×18
=100+324
=424cm
2
(iii) Area = area of trapezium EDAF+ area of □ABCD [ref. image (iii)]
=
2
8
×(6+20)+20×20
=4×26+400
=104+400
=504cm
2
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