Question

find the area of equilateral
triangle those side are 5 cm

find the area of trangle those
base is 13.2 and hight=17.11h​

Answer 1

=1/2*5*5=12.5

=1/2*13.2*17.11

=6.6*17.11

=112.96

hope this helps u

Answer 2

$\mathfrak{1st\; answer}$

Given, side of the equilateral is 5cm.

We know,the formula to find the area of an equilateral triangle, which is $\frac{\sqrt3}{4}\times a^2$ Where, a is the side of the triangle. Putting value in the formula

$\frac{\sqrt3}{4}\times 5^2\\ \\ \frac{\sqrt3}{4}\times 25\\ \\ \frac{25\sqrt3}{4}\\ \\ Putting,\ \sqrt3=1.732\ in\ the\ equation \\ \\ \frac{25\times 1.732}{4}\\ \\ \implies10.825\\ \therefore \text {the area of the equilateral triangle is} 10.825cm^2$

$\mathfrak{2nd\; answer}$

Given,

height of the triangle=17.11

base of the triangle=13.2

We need to find the area of the triangle,

$\text{Area of the triangle}=\frac{1}{2}\times base \times height$

Putting values in the formula

$\frac{1}{2}\times 13.2 \times 17.11\\ \\ \therefore \text{The area of this triangle is} \bold{112.926cm^2.}$