Question

Find the area of equilatetal triangle with side 2√3 by herons formulae

Answer 1

Answer:-

1.73 is the answer

Answer 2

Answer:

${\fbox{\huge{\tt{Solution\::}}}}$

Step-by-step explanation:

Herons'Formula :-

a+b+c/2 = s

(where "s" is semiperimeter)

(2√3+2√3+2√3)/2

or, 3(2√3)/2= 6*9/2

or, 54/2 , 27

Area = √[s(s-a) (s-b) (s-c)]

= √[27*3*(27-2√3)]

= √[27 * 81-54]

= √[27*27]

= 27

Or, by using equilateral triangle formula

Area = (√3/4)a² [where a= 2√3)

= (√3/4)*(2√3)²

= (√3/4)*(4*9)

= (√3/4)*(36)

= 9√3