find the area of field abcdefgh fig (5) given aside in which bc=28m bg=21m am=18m dn=12.8m and ed=14m
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Answer:
Area of field = 1002 m²
Step-by-step explanation:
Since BCFG is a rectangle, area = length × breadth = BC* BG = 28 * 21 = 588 m² ---------------------(1)
Area of △ABG = 12 * base * height = 12 * 21 *18 = 189 m² ---------------------(2)
Area of trapezium EDCF=12 (Sum of parallel sides) * height = 12 * (ED+ FC) * ND = 12 * (21+14) * 12.8 = 6.4 * 35 = 225 m² ---------------------(3)
Area of the given figure = sum of 1, 2 and 3 = 189 + 225 + 588 = 1002 m².
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