Question

Find the area of figure ABCP. (Take π= 22/7)
On diameter AC a semi-circle is drawn.
AB = BC = 7 cm.​

Answer 1

Answer:

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Answer 2

AnsweIn right angled triangle ABC,

we have

AC

2

=AB

2

+BC

2

AC

2

=14

2

+14

2

AC=

2×14

2

​

=14

2

​

 cm

Now required Area

=Area APCQA

=Area ACQA - Area ACPA

=Area ACQA - (Area ABCPA - Area of Δ ABC)

=

2

1

​

×π×(

2

14

2

​

​

)

2

−[

4

1

​

×π(14)

2

−

2

1

​

×14×14]

=

2

1

​

×

7

22

​

×7

2

​

×7

2

​

−

4

1

​

×

7

22

​

×14×14+

2

1

​

×14×14

=154−154+98

=98 cm

2

r:

Step-by-step explanation: