Find the area of following figure:
1.2 cm
3.6 cm
1 cm
2 cm
8 cm
2.4 cm
Answers
The area of the figure is 22 cm²
Step-by-step explanation:
In the figure, we can see a rectangle ABEF and an isosceles trapezoid BCDE.
Therefore, the total area is the sum of the area of the rectangle and the area of the isosceles trapezoid.
Area of the rectangle ⇒
The area of the rectangle is the product of length and breadth. That is,
A=l\times bA=l×b
Length, AB = EF = 8 - 2.4 = 5.6 cm
Breadth, AF = BE = 2 cm
Hence the area, A=5.6\times 2=11.2\ cm^{2}A=5.6×2=11.2 cm
2
Area of the isosceles trapezoid ⇒
The area of an isosceles trapezoid can be found by the following formula. That is,
A=\dfrac{a+b}{2} \times hA=
2
a+b
×h
Where 'a' and 'b' are the parallel sides of the trapezoid and 'h' is the height.
a = 2 cm
b = 7 cm
h = 2.4 cm
Then,
\begin{gathered}A=\dfrac{2+7}{2} \times 2.4\\\\A=4.5\times 2.4=10.8\ cm^{2}\end{gathered}
A=
2
2+7
×2.4
A=4.5×2.4=10.8 cm
2
∴ The total area = Area of the rectangle + Area of the isosceles trapezoid
The total area = 11.2 + 10.8
= 22 cm²