Question

Find the area of following triangles by heron 's formula and also find the length of the height corresponding its largest side 9cm, 12cm,15cm

Answer 1

Answer:

area of triangle=

Step-by-step explanation:

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give ne brianlist

Answer 2

Answer:

$side \: are \: : a = 9 \\ b = 12 \: \: \: \: \: \: \: c = 15 \\ area \: = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2} \\ = \frac{9 + 12 + 15}{2} \\ = \frac{36}{2} = 18 \: \\ area = \sqrt{18(18 - 12)(18 - 9)(18 - 15)} \\ = \sqrt{18 \times 6 \times 9 \times 3 } \\ = \sqrt{(2 \times {3}^{2}) \times (2 \times 3) \times {3}^{2} \times 3 } \\ = \sqrt{ {2}^{2} \times {3}^{2} \times {3}^{2} } \\ = 2 \times 3 \times 3 = 18$

$corresponding \: height \: of \: a \\ = h1 \\ corresponding \: height \: of \: b \\ = h2 \\ corresponding \: height \: of \: c \\ = h3 \\ area \: = \frac{a \times h1}{2} = \frac{b \times h2}{2} \\ = \frac{c \times h3}{2 } \\ h1 = \frac{area \: \times 2}{a} = \frac{18 \times 2}{9} = 4 \\ h2 = \frac{area \: \times 2}{b} = \frac{18 \times 2}{12} = 3 \\ h3 = \frac{area \times 2}{c} = \frac{18 \times 2}{15} = \frac{12}{5}$