Question

find the area of following triangles having sides given.(heron's formula). a=7cm b=7cm c=8cm​

Answer 1

Answer:

4√33

Step-by-step explanation:

area = √(s(s - a)(s-b)(s-c))

S = (7+7+8)/2

= 22/2 = 11

area^2 = 11*4*4*3

area^2 = 528

area = √528

area = 4√33

Answer 2

Answer:

Given :- A=7cm

B= 7cm

C= 8cm

Therefore ,

1. S = A + B + C / 2
2. 7+ 7+8/2= 22/2 = 11
3. Since S = 11
4. Therefore Area of Triangle (A) =
5. $\sqrt{s \times < s - a > \times < s - b > \times < s - c > }$

• $\sqrt{11 \times < 11 - 7 > \times < 11 - 7 \times < 11 - 8 > }$
• $\sqrt{11 \times 4 \times 4 \times 3}$
• $\sqrt{528}$

$16 \sqrt{33cm {}^{2} }$

• It is the answer