find the area of four Walls of a room whose dimension are 6mx5mx3mx . find the cost of painting the walls at Rs 10 per cm
Answers
Answer:
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m
2
Area of the ceiling is:
A=l×b=8×5=40 m
2
Total area of the four walls and the ceiling of the room is 78+40=118 m
2
It is given that cost of white washing is Rs.15/m
2
, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
Given:
✰ Length of a room = 6 m
✰ Breadth of a room = 5 m
✰ Height of a room = 3 m
To find:
✠ The area of four walls of a room.
✠ The cost of painting the walls at Rs. 10 per cm²
Solution:
First we will find the area of four walls of the room by using formula..Putting the values in the formula and then doing the required calculations. After that we will convert the given area of a four walls which is in metres into centimetre units, because for finding the cost, the nature of the unit should be same. Then, we will find the cost of painting the walls at Rs. 10 per cm².
Let's find out...✧
✭ Area of 4 walls of the room = 2(l + b) × h ✭
Where,
l is the length of a room.
b is the breadth of a room.
h is the height of a room.
Putting the values in the formula, we have:
➤ Area of 4 walls of the room = 2 ( 6 + 5 ) × 3
➤ Area of 4 walls of the room = 2 × 11 × 3
➤ Area of 4 walls of the room = 22 × 3
➤ Area of 4 walls of the room = 66 m²
∴ The area of four walls of the room = 66 m²
⤳1 m² = 100 × 100 cm²
⤳66 m² = 66 ( 100 × 100 ) cm²
⤳660000 cm²
Now,
➛ The cost of painting the walls per cm² = Rs. 10
➛ The cost of painting the walls per 660000 cm² = 10 × 660000
➛ The cost of painting the walls per 660000 cm² = Rs. 6,600,000
∴ The cost of painting the walls = Rs. 6,600,000
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