Question

Find the area of four walls of a room whose length ,breadth and height are 8m,6.5m and 3.5m​

Answer 1

$\huge \underline{ \underline{ \pink{ \purple✯ \: Aɴsᴡᴇʀ \: \purple{ ✯}}}}$

we know that, if ’l’ is Length, ‘b’ is breadth and ‘h’ is the height of the room, then

$\boxed{ \bold{area \: of \: four \: walls \: = 2 \times (l + b) \times h}}$

$\implies 2 \times (8 + 6.5) \times 3.5 \\ \\ \implies 2 \times 14.5 \times 3.5 \: \: \: \: \: \: \: \: \: \\ \\ \implies 31.5 \: \bold{{m}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

hence, area of the four walls is 31.5 m²

Answer 2

$\huge\boxed{\fcolorbox{pink}{green}{ᎪղรᴡᎬя}}$

we know that, if ’l’ is Length, ‘b’ is breadth and ‘h’ is the height of the room, then

$\boxed{ \bold{area \: of \: four \: walls \: = 2 \times (l + b) \times h}} </p><p></p><p>\begin{gathered} \implies 2 \times (8 + 6.5) \times 3.5 \\ \\ \implies 2 \times 14.5 \times 3.5 \: \: \: \: \: \: \: \: \: \\ \\ \implies 31.5 \: \bold{{m}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered} </p><p>⟹2×(8+6.5)×3.5</p><p>⟹2×14.5×3.5</p><p>⟹31.5m^{2}$

hence, area of the four walls is 31.5 m²