find the area of four walls of a room whose length is 18m breadth 16m and height 13m
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find the area of four walls of a room whose length is 18m breadth 16m and height 13m
Length (l) = 18 m
Breadth (b) = 16m
Height (h) = 13m
FORMULA ➡ 2h ( l + b)
Therefore area of the four walls will be,
➡ 2 * 13m ( 18m + 16m)
➡ 26m ( 34 m)
➡ 884 m^2
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CSA of room = 2h(l+b)
= 2×13(18+16)
=26(34)
=884
area of four walls of a room is 884m^2
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