Math, asked by ProAth128, 4 days ago

Find the area of given fig. below as the sum of areas if two trapezium and a rectangle​

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Answers

Answered by pranavglam
0

Answer:

900 sq. cm

Step-by-step explanation:

Area of trapezium = 1/2 x ( 10 + 30) x 10 = 200

area of rectangle = 500

total area = 500 + 2 x 200 = 900 sq. cm

Answered by manikandanmanik07
0

Answer:

Step-by-step explanation:

Area of figure = Area of two trapeziums + Area of rectangle

Given that,

Length of rectangle = 50 cm

Breadth of rectangle = 10 cm

Length of parallel sides of trapezium = 30 cm and 10 cm

Distance between parallel sides of trapezium = (70-50)/2 = 20/2 = 10

So, Distance between parallel sides of trapezium = 10 cm

Area of figure = 2 x 1/2 (Sum of lengths of parallel sides) * altitude + Length x Breadth

Area of figure = 2 × 1/2 (30+10) × 10 + 50 ×

10

Area of figure = 40 × 10 + 50 × 10

Area of figure = 400 + 500 = 900

... Area of figure = 900 cm²

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