Find the area of given fig. below as the sum of areas if two trapezium and a rectangle
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Answer:
900 sq. cm
Step-by-step explanation:
Area of trapezium = 1/2 x ( 10 + 30) x 10 = 200
area of rectangle = 500
total area = 500 + 2 x 200 = 900 sq. cm
Answered by
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Answer:
Step-by-step explanation:
Area of figure = Area of two trapeziums + Area of rectangle
Given that,
Length of rectangle = 50 cm
Breadth of rectangle = 10 cm
Length of parallel sides of trapezium = 30 cm and 10 cm
Distance between parallel sides of trapezium = (70-50)/2 = 20/2 = 10
So, Distance between parallel sides of trapezium = 10 cm
Area of figure = 2 x 1/2 (Sum of lengths of parallel sides) * altitude + Length x Breadth
Area of figure = 2 × 1/2 (30+10) × 10 + 50 ×
10
Area of figure = 40 × 10 + 50 × 10
Area of figure = 400 + 500 = 900
... Area of figure = 900 cm²
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