Question

find the area of given figure​

Answer 1

Step-by-step explanation:

area of trapezium =(a+b)×h/2

=(26+29)21/2

=55×21/2

=1155/2

=577.5cm sq.

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Answer 2

Explanation of diagram [ refer attached picture for diagram ] :-

=> AB is parallel to DC .

=> Length of AB = 26 cm

=> Length of DC = 29 cm

=> Distance between AB and DC =21 cm. This means AD = 21 cm. AD is considered height of trapezium.

Now we will find out the area of given trapezium.

We know that :-

$\boxed{\tt Area \: of \: Trapezium = \dfrac{1}{2} \times (sum \: of \: parallel \: sides) \times (distance \: between \: parallel \: sides)}$

$\tt \longrightarrow Area \: of \: Trapezium = \dfrac{1}{2} \times (26 + 29) \times (21)$

$\tt \longrightarrow Area \: of \: Trapezium = \dfrac{1}{2} \times 55 \times 21$

$\tt \longrightarrow Area \: of \: Trapezium = \dfrac{1}{2} \times 1155$

$\tt \longrightarrow Area \: of \: Trapezium = \dfrac{1155}{2} = 577.5 \: {cm}^{2}$

Answer :

Area of given trapezium = 577.5 cm²

$\tt \underline{\red{Additional- Information}}$

1. Area of circle = π r²

2. Area of square = (side)²

3. Area of rectangle = length × breath

4. Circumference of circle = 2πr

5. Perimeter of square = 4 × side

6. Perimeter of rectangle = 2( length+breadth)

7. Perimeter of any figure = sum of all sides of that figure