Math, asked by hemaknttyagimath, 3 months ago

Find the area of given figure​

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Answered by mahatochnimai
0

Answer:

Step-by-step explanation:

Base of Triangle DEG

H^2=P^2+B^2

5^2=4^2+B^2

25=16+B^2

25-16=B^2

9=B^2

\sqrt9=B

3=B

Therefore,B[EG]= 3CM

THEREFORE, area of triangle DEG=\frac{1}{2}*b*h

                                                          \frac{1}{2}*3*4

                                                          3*2

                                                           6CM^2

triangle DEG=triangle CEF

THEREFORE TRIANLE CEF=6CM^2

TOTAL=6+6=12CM^2

THEREFORE,AREA OF SQUARE ABCD=SIDE*SIDE

                                                                   6*6

                                                                     36CM^2

THEREFORE TOTAL AREA OF THE FIGURE =36+12

                                                                             48CM^2

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