Find the area of given figure
Answers
Answer:
Step-by-step explanation:
Base of Triangle DEG
H^2=P^2+B^2
5^2=4^2+B^2
25=16+B^2
25-16=B^2
9=B^2
=B
3=B
Therefore,B[EG]= 3CM
THEREFORE, area of triangle DEG=*b*h
*3*4
3*2
6CM^2
triangle DEG=triangle CEF
THEREFORE TRIANLE CEF=6CM^2
TOTAL=6+6=12CM^2
THEREFORE,AREA OF SQUARE ABCD=SIDE*SIDE
6*6
36CM^2
THEREFORE TOTAL AREA OF THE FIGURE =36+12
48CM^2
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