Math, asked by aryanparashar2668, 3 months ago

find the area of given figure​

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Answered by GARIMA672
1

Answer:

Area of trapezium YXUT= 1/2(a+b)h

=(1/2)(10+12)(7)

=(1/2)(22)(7) = 77cm²

Area of trapezium SRUT= 1/2(a+b)h

=(1/2)(12+8)(5)

=(1/2)(20)(5)

=50 cm²

Area of rectangle PQRS=l*b

8*5=40cm²

Area of figure= YXUT+SRUT+PQRS

=77+50+40 cm²

=167cm²

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