Question

Find the area of given figure.
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Answer 1

Answer:

Let O be the centre of the hexagon

It follows that the point O, when joined to the ends of a side of the hexagon forms an equilateral triangle.

∴AO=BO=CO=DO=EO=FO=10cm=0.1 m

Since at each comer of the hexagon, a charge of 5pc i.e., 5×10−6C is placed, total electric potential at point o due to the charges at the six comers,

V=6×(

4π∈

0

1

×

r

q

)

=6×9×10

9

×

0.1

5×10

−6

=2.7×10

6

V.

2...AB

2

=AD

2

+BD

2

AB

2

=25

⇒AB=5

AC

2

=AB

2

+CB

2

AC

2

=5

2

+12

2

AC

2

=169

⇒AC=13

cotθ=

AB

CB

=

5

12

Answer 2

Find the area of given figure.

Tomorrow I will get it to you