Math, asked by shubhamgautam8707, 11 months ago

Find the area of given figure.​

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Answered by Anonymous
1
area SRPQ = 8*5 = 40cm²

area of SRUT = 5(8+12)/2=50cm²

area of TUXY = 7(10+12)/2 = 77cm²

TOTAL AREA = 77+50+40 =167cm²
Answered by Kshitij2407
3
Area of trapezium TUXY= 1/2*×(sum of parallel sides)×height
=1/2×(10cm+12cm)×7cm
=1/2×22cm×7cm=
=11cm×7cm
=77cm²

Area of trapezium SRUT= 1/2×(sum of parallel sides)×height
=1/2×(8cm+12cm)×5cm
=1/2×20cm×5cm
=10cm×5cm
=50cm²

Area of rectangle PQRS = L×B
=8cm×5cm
=40cm²

Area of figure = Area of trapezium TUXY + Area of trapezium SRUT + Area of rectangle PQRS
=77cm²+ 50cm²+ 40cm²
=167cm²
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