Find the area of given figure ABCD. A 2cm 3cm 2cm D B 2cm 2cm C
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Answer: (3√7/4 + √3) cm².
Explanation:
ar(ABCD) = ar(∆ABD) + ar(∆BCD)
=> Area = (√3)/4 × 2 × 2 + [3/2√(2)² - (3)²/4]
[Area of an equilateral triangle = (√3)/4 × s² & Area of an isoscles triangle = b/2(√a² - b²/4).]
=> Area = √3 + 3/2(√4 - 9/4)
=> Area = √3 + 3/2[√(16 - 9)/4]
=> Area = 3/2(1/2√7) + √3
=> Area = (¾√7 + √3) cm².
ALITER: You can also use the Heron's formula to find the area.
∆ = √[s(s - a)(s - b)(s - c)]
where, s = (a + b + c)/2.
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