Find the area of given quadrilaterals..
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sakshi574:
please give me the answers
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1. Area of quadrilateral =area of 1st triangle=1/2*base*height
= 1/2*8*3cm^2
=4*3cm^2
=12 cm^2
+area of 2nd triangle
=1/2*base*height
=1/2*8*4cm^2
=4*4cm^2
=16cm^2
So,
area of 1st triangle +area of 2nd triangle
=12cm^2 +16cm^2
=28cm^2
2. Area of quadrilateral =area of 1st triangle
=1/2*base *height
=1/2*8*10cm^2
=4*10cm^2
=40cm^2
+area of 2nd triangle
=1/2*base*height
=1/2*10*1cm^2
=5cm^2
=area of 1st triangle +area of 2nd
triangle
=40cm^2 +5cm^2
=45cm^2
____________________________________
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HAVE A GOOD DAY
1. Area of quadrilateral =area of 1st triangle=1/2*base*height
= 1/2*8*3cm^2
=4*3cm^2
=12 cm^2
+area of 2nd triangle
=1/2*base*height
=1/2*8*4cm^2
=4*4cm^2
=16cm^2
So,
area of 1st triangle +area of 2nd triangle
=12cm^2 +16cm^2
=28cm^2
2. Area of quadrilateral =area of 1st triangle
=1/2*base *height
=1/2*8*10cm^2
=4*10cm^2
=40cm^2
+area of 2nd triangle
=1/2*base*height
=1/2*10*1cm^2
=5cm^2
=area of 1st triangle +area of 2nd
triangle
=40cm^2 +5cm^2
=45cm^2
____________________________________
I HOPE THIS WILL HELP YOU MARK ME AS THE BRAINLIEST ANSWER......................................
HAVE A GOOD DAY
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