Question

Find the area of Iron required to make a open cubical tank whose length is 8m,breadth is 6m and height is 2 m. Also, find the cost of iron used at the the rate of 60 per square meter

Answer 1

the answer is rs. 912.

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The cost of iron used is Rs. 9120.}}}$

Step-by-step explanation:

Given measures of the length, breadth and height of the cubical tank are

l = 8m, b = 6m  and  h = 2m.

So, the surface area of the cubical tank is

$S.A.\\\\=2(lb+bh+lh)\\\\=2(8\times6+6\times2+8\times2)\\\\=2(48+12+16)\\\\=152.$

Also, to cover 1 sq m, the cost of iron used = Rs. 60.

Therefore, the cost of iron used to cover 152 sq. m is given by

$Rs.(152\times60)=Rs. 9120.$

Thus, the required cost of iron is Rs. 9120.

Learn more#

Question : A cubical tank open at the top is made of an iron sheet 4 m wide. if the dimensions of the tank are 12 m  * 8 m  * 6 m find the cost of an iron sheet required to make the tank at Rs.17.50 per meter.

Link : https://brainly.in/question/3177.