Question

find the area of isoceles triangle whose each equal side is 5 cm and third side is 8 cm​

Answer 1

Answer:

$are \: of \: triangle = \sqrt{s(s - a)(s - b)(s - b)} \\ s = \frac{a + b + c}{2} \\ s = \frac{5 + 5 + 8}{2 } = \frac{18}{2} = 9 \\s = \sqrt{9(9 - 5)(9 - 5)(9 - 8) } \\ s = \sqrt{9(4)(4)(1)} \\ s = \sqrt{9 \times 4 \times 4 \times 1 } \\ s = 3 \times 2 \times 2 \times 1 \\ s = 12 {cm}^{2}$

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