Question

find the area of isoceles triangle whose equal side is 6cm,6cm and 8cm​

Answer 1

Answer:

s=6+6+8/2 = 10 cm

Area =8√2 cm ²

Answer 2

Step-by-step explanation:

Given :

Two equal sides of an isosceles triangle are 6cm each.

Third side of the triangle is 8cm.

To Find :

Area of the isosceles triangle.

Solution :

a = 6cm.

b = 6cm.

c = 8cm.

\longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s=

2

a+b+c

\longmapsto\tt{s=\dfrac{6+6+8}{2}}⟼s=

2

6+6+8

\longmapsto\tt{s=\cancel\dfrac{20}{2}}⟼s=

2

20

\longmapsto\tt\bold{s=10cm}⟼s=10cm

Now ,

\longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area=

s(s−a)(s−b)(s−c)

\longmapsto\tt{\sqrt{10(10-6)(10-6)(10-8)}}⟼

10(10−6)(10−6)(10−8)

\longmapsto\tt{\sqrt{10\times{4}\times{4}\times{2}}}⟼

10×4×4×2

\longmapsto\tt{\sqrt{5\times{2}\times{2}\times{2}\times{2}\times{2}\times{2}}}⟼

5×2

×2×2×2×2×2

\longmapsto\tt{2\times{2}\times{2}\sqrt{5}}⟼2×2×2

5

\longmapsto\tt\bold{8\sqrt{5}{cm}^{2}}⟼8

5

cm

2

So , The Area of the isosceles triangle is 8√5cm²

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