find the area of isocess triangle whose base is 16 cm and one of its equal side is 10cm
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Answered by
0
Answer:
area of triangle is b/2×h
Step-by-step explanation:
16/2×10=8×10=80
Answered by
1
The area of triangle is 48 sq cm
Step-by-step explanation:
if we draw the Perpendicular at the base
the height can be calculated as follows
let the height be x
8² + x² = 10²
64 + x² = 100
x² = 100 - 64
x² = 36
x = √36
x = 6
therefore area of triangle = 1/2 * base * height
= 1/2 * 16 *6
= 48 sq cm
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