find the area of isosceles triangle having base 2cm amd length 4cm.(by heron's formula)
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Answered by
2
Hi Friend !!!
Here is ur answer !!!!
sides are :
a= 4cm
b = 4cm
c = 2cm
S = a+b+c/2
= 4+4+2/2
= 10/2
= 5
Area = √s(s-a) (s-b)(s-c)
= √5(5-4)(5-4)(5-2)
= √5(1)(1)(3)
= √15 cm²
Hope it helps u : )
Here is ur answer !!!!
sides are :
a= 4cm
b = 4cm
c = 2cm
S = a+b+c/2
= 4+4+2/2
= 10/2
= 5
Area = √s(s-a) (s-b)(s-c)
= √5(5-4)(5-4)(5-2)
= √5(1)(1)(3)
= √15 cm²
Hope it helps u : )
Answered by
0
semi perimeter =(2+4+4)/2=5 cm
area =√s (s-a)(s-b)(s-c)=3.872 sq.cm
area =√s (s-a)(s-b)(s-c)=3.872 sq.cm
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