Question

find the area of isosceles triangle whose base is 16cm and one of its equal sides is 10cm

Answer 1

Hiii friend,


Let ∆ABC be an isosceles triangle.


In which BC is base and AB , AC is two equal sides


Given :- Base (B) = 16 cm


Two equal sides AB and AC (A)= 10 cm


Therefore,


Area of ∆ABC = 1/4 × B × ✓4A²-B² cm².


=> 1/4 × 16 × ✓ 4 × (10)² - (16)²


=> 4 × ✓4 × 100 - 256


=> 4✓400 - 256


=> 4✓144


=> 4 × 12


=> 48 cm².



HOPE IT WILL HELP YOU...... :-)

Answer 2

hope this will help you ......