Find the area of isosceles triangle whose equal sides are 10cm each and other side is 1cm
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Perimeter of triangle =28 -(given)
Perimeter of triangle=sum of all (three) sides
Let's take 3 sides are a,b,c
Given that, triangle is isosceles
Hence 2 sides are equal let's take a & b are two equal sides of triangle (a=b ) then ,
a+b+c=28 but,
a=b therefore
2a+c=28
Put a=b=10
We get
C=8-third side of triangle
Perimeter of triangle=sum of all (three) sides
Let's take 3 sides are a,b,c
Given that, triangle is isosceles
Hence 2 sides are equal let's take a & b are two equal sides of triangle (a=b ) then ,
a+b+c=28 but,
a=b therefore
2a+c=28
Put a=b=10
We get
C=8-third side of triangle
anuragdixit80:
where is area???
how to get perimeter
you have to use herons formula
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it's incorrect question
What is the area of an isosceles triangle with two equal sides of 10 cm and other side 12 cm?
it's correct answer
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