Find the area of isosceles triangle whose equal sides is a & base b
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Method 1:
Find the height by the square root of (½b)²+a², then find the area by ½*base*height
Method 2:
Use the heron's formula where area is
√s(s-a)(s-b)(s-c), where:
a,b and c are the sides of the triangle
s is the semi perimeter which is equal to ½ of (a+b+c)
since it is an isosceles triangle, your formula will become √s(s-a)(s-a)(s-b)
Method 3:
Use this formula:
¼*b*√4a²+b², where
a=length of each equal side
b=length of base
Find the height by the square root of (½b)²+a², then find the area by ½*base*height
Method 2:
Use the heron's formula where area is
√s(s-a)(s-b)(s-c), where:
a,b and c are the sides of the triangle
s is the semi perimeter which is equal to ½ of (a+b+c)
since it is an isosceles triangle, your formula will become √s(s-a)(s-a)(s-b)
Method 3:
Use this formula:
¼*b*√4a²+b², where
a=length of each equal side
b=length of base
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