Question

Find the area of isosceles triangle whose one of equal sides is b and base is a
(Ans14b2 - 42 )​

Answer 1

Answer:

In an isosceles triangle, altitude is bisect to base. Therefore,

Altitude =(Sidelengthofequalside)2−(2base)2=b2−4a2

Now, area of isosceles △=21×altitude×base

                                            =21×b2−4a2×a

                                            =41×a4b2−a2