Question

find the area of isosceles triangle whose two equal sides are 5 cm and third side is 8cm photo khich kr bhejni hai tbhi Branliest answer dunga​

Answer 1

$\sf\large{\red{\underbrace{Answer \implies 12\:{cm}^{2}}}}$

$\sf\large{\underline{\underline{For\: Rt. \:Triangle\: ADB}}}$

$\sf\large{By\:Pythagoras\:Throrem}$

$\sf\large{\red{\implies {AB}^{2} = {BD}^{3} + {AD}^{2}}}$

$\sf\large{\purple{\implies AD = \sqrt{{AB}^{2} - {BD}^{2}}}}$

$\sf\large{\orange{\implies AD = \sqrt{{5}^2} - {4}^{2}}}$

$\sf\large{\green{\implies AD = \sqrt{25 - 16}}}$

$\sf\large{\red{\implies AD = \sqrt{9} = 3\:cm}}$

$\sf \large{\underline{\underline{Now:}}}$

$\sf\large{Area\: of\:triangle\:ADB = \dfrac{1}{2} × Base × Height}$

$\sf\large{\purple{\implies \dfrac{1}{2} × 4 × 3 = 6\:{cm}^{2}}}$

$\sf\large{\underline{\underline{Similarly:}}}$

$\sf\large{\orange{Area\:of\:triangle\:ADC = 6\: {cm}^{2}}}$

$\sf\large{\underline{\underline{Therefore:}}}$

$\sf\large{Area\:of\:triangle\:ABC}$

$\sf\large{ = area\:of\:triangle\:ADC + Area\:of\:triangle\:ADB}$

$\sf\large{\red{\implies 6 + 6}}$

$\sf\large{\orange{\implies 12\:{cm}^{2}}}$