Question

find the area of isosceles triangle with unequal side as 10 cm and each equal side is 12 CM​

Answer 1

Answer:

5√119 cm²

Step-by-step explanation:

Let the sudes of isosceles triangle be a, b and c respectively.

a = 10 cm

b = 12 cm

c = 12 cm

Using Heron's Formula ;

S = $\large{\frac{\text{a+b+c}}{2}}$

S = $\large{\frac{10+12+12}{2}}$

S = $\large{\frac{34}{2}}$

S = 17 cm

Area = $\sqrt{\text{s(s-a)(s-b)(s-c)}}$

Area = $\sqrt{17(17-10)(17-12)(17-12)}$

Area = $\sqrt{17 \times 7 \times 5 \times 5}$

Area = $5 \sqrt{17 \times 7}$

Area = 5√119 cm²

Hence, the area of triangle is 5√119 cm²