Question

Find the area of isosceles triangle with unequal sides as 8 CM and each equal side as 5 cm​

Answer 1

Answer:

4√41

Step-by-step explanation:

Area of triangle =1/2 (Base * Height)=1/2*8*√41=4√41

Answer 2

Area of isosceles traingle is 12 cm².

Given:

• An isosceles traingle.
• With one side 8 cm and two equal sides are 5 cm.

To find:

• Find area of triangle.

Solution:

Formula to be used:

Apply Heron's formula: If a,b and c are the length of sides of a triangle, then area of triangle is given by

$\bf Ar.(\triangle)= \sqrt{s(s - a)(s - b)(s - c)}$

where, s is semi perimeter of triangle.

Step 1:

Find the semi perimeter of triangle.

Let sides are say

$a = 5 \\ b = 5 \\ c = 8$

So,

$s = \frac{5 + 5 + 8}{2}$

or

$\bf s = 9$cm

Step 2:

Find area of triangle.

Apply Heron's formula.

$Ar.(\triangle)= \sqrt{9(9 - 5)(9 - 5)(9 - 8)}$

or

$Ar.(\triangle) = \sqrt{9 \times 4 \times 4 \times 1}$

or

$Ar.(\triangle) = 3 \times 4$

or

$\bf \red{Ar.(\triangle) = 12 \: {cm}^{2}}$

Thus,

Area of isosceles traingle is 12 cm².

#SPJ3

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