Question

find the area of isoscle triangle having the base is ,x cm and one side y cm​

Answer 1

Answer:

area of isosceles ∆ = 1/2 (x)^2 × (y^2 - 1/2 x^2)

hope you got your answer

Answer 2

$\huge\bold\green{ solution }$

isosceles triangle ;

where two sides of triangle is equal

let , triangle "A" and "B" = x

and another side be = y

$area \: of \: isosacles \: = \frac{1}{4} b \sqrt{4a ^{2} - b^{2} } \\ \\ = \frac{1}{4} b \sqrt{4x ^{2} - y ^{2} } \\ \\ = \frac{1}{4} 2bx - y \\ \\ \frac{1}{2} bx - y$

hence, area of isosceles ∆= 1/2 bx-y