Question

Find the area of isoscles triangle each of whose equal side measure 13cm and whose base measure 20cm​

Answer 1

Answer:

10√46

Step-by-step explanation:

we need to use herons formula

area = √s(s-a)(s-b)(s-c)

s = (a+b+c)/2

a, b, c are sides of triangle

$s = \frac{13 + 13 + 20}{2} = \frac{46}{2} = 23 \\ area \: = \sqrt{23(23 - 13)(23 - 13)(23 - 20)} \\ = \sqrt{23 \times 10 \times 10 \times 3} \\ = 10 \sqrt{46}$

Answer 2

We have three sides- 13cm,13cm and 20cm, you can easily find the perimeter by using heron's formula

 First of all- we need to get the semi-perimeter

s=a+b+c/2=13+13+20/2

=46/2=23

now, put the heron's formula i.e. √s(s-a)(s-b)(s-c)

=√23(23-13)(23-13)(23-20)

=√23*10*10*3

=√23*2*5*2*5*3

=10√23*3

=10√69

=83.07cm^2 (approx.)