Question

Find the area of loop of the curve y^2=(x-1)(x-3)^2

Answer 1

Step-by-step explanation:

Hay Guys!!!!

Find the area of the loop of the curve

y^2=x^3(1-x)^2 using integral calculus.

y=√x^3(1-x)^2 y=√x^3/2 (1-x)

To sketch the curve, I assigned values for x and then solved the corresponding values of y

. x= -1,

y= -2

x= -0.5,

y= -0.53

x=0,

y= 0

x= 0.5,

y= 0.177

x=1,

y=0

Hope it may help to you

Answer 2

hey dude !!!

$\\ \\ \\ {y}^{2} = (x - 1) {(x - 3)}^{2}$

to sketch the curve, assign values of X and Y ..

$\\ \\ x = - 1 \\ \\ x = - 0.5\\ \\ x = 0 \\ \\ x = 0.5 \\ \\ x = 1 \\ \\ y = - 2 \\ \\ y = 0.53 \\ \\ y = 0 \\ \\ y = 0.177 \\ \\ y = 0$

hope this helps you