Find the area of metal sheet required in making a closed hollow cone of base radius 7 cm and height 24 cm.
Answers
Given : Base radius of cone, r = 7 cm
Height of cone, h = 24 cm
Slant height of cone, l = √r² + h²
l = √(24² +7² )
l = √625
l = 25 cm
Area of metal sheet required = Total surface area of cone (T.S.A)
[Metal sheet is closed]
T.S.A of cone = πr(l + r)
T.S.A of cone = 22/7 × 7 (25 + 7)
T.S.A of cone = 22 × 32
T.S.A of cone = 704 cm²
Hence, Area of metal sheet required is 704 cm²
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Given :
- r = 7 cm
- h = 24 cm
By pythagoras therome
l = √r² + h²
l = √(24² +7² )
l = √625
l = 25 cm
Now,
Area of metal sheet required = Total surface area of cone
T.S.A of cone = πr(l + r)
T.S.A of cone = 22/7 × 7 (25 + 7)
T.S.A of cone = 22 × 32
T.S.A of cone = 704 cm²